Another hard SAT math question
This is a “hard” SAT math problem:
The length of rectangle S is 20 percent longer than the length of rectangle R, and the width of rectangle S is 20 percent shorter than the width of rectangle R. The area of rectangle S is
A. 20% greater than the area of rectangle R
B. 4% greater than the area of rectangle R
C. equal to the area of rectangle R
D. 4% less than the area of rectangle R
E. 20% less than the area of rectangle R
Joey said,
November 7, 2006 @ 4:55 pm
ew more math
aqian said,
November 7, 2006 @ 5:55 pm
Well, Jinghao is all about math.
And I would do that question. But again, I’m in college. “Who cares?”
Jinghao said,
November 8, 2006 @ 10:25 pm
Oh come on, we all love math
aqian said,
November 12, 2006 @ 3:05 pm
1 + 1 = 2
YAYYYYYY